Calculate the molality of a solution by dissolving 0.850g ofammonia (NH3) in 100g of water.
Answers
Answered by
5
Molality = moles of the solute ÷ mass of the solvent (kg)
moles of NH3 = 0.850 ÷ 17 = 0.05
100 g = 0.100 kg
Molality = 0.05 / 0.100 = 0.5 m
moles of NH3 = 0.850 ÷ 17 = 0.05
100 g = 0.100 kg
Molality = 0.05 / 0.100 = 0.5 m
Answered by
2
Answer:
mark as brainliest
Explanation:
thankyou
Attachments:
Similar questions
Computer Science,
8 months ago
History,
1 year ago
Physics,
1 year ago
English,
1 year ago
Physics,
1 year ago