Question

Calculate the number of
(a) oxygen atoms in 0.10 mole of Na2Co3. 10H20

the answer is 7.8 x 10^23
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Answer 1

Answer:

Since 1 mole of Na2CO3.10H20 = 6.022 X1023molecules of Na2CO3.10H20

So 0.1 mol of Na2CO3.10H2O will have = 6.022 X1023 X0.1 molecules of Na2CO3.10H20

Now we know that each molecule contains 13 O-atoms,

Total no. of O- atoms = 6.022 X1022 X 13

hence O2 molecules will be = 6.022 X1022 X 13 /2= 6.022 X1022 X 6.2

Now further, 6.022 X1023 molecules of Oxygen = 1 mol Oxygen gas .

Thus,  6.022 X1022 X 6.2 molecules of Oxygen will contain=  6.022 X1022 X 6.2 / 6.022 X1023 moles of oxygen

= 0.62 mol of oxygen

Now as one mol oxygen = 32 gm of oxygen

So, 0.62 mol oxygen = 32 X 0.62= 19.84 gm of Oxygen gas..

Answer 2

Explanation:

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