Question

calculate the number of moles of oxygen require to produce 240g magnesium oxide by burning magnesium metal??

Answer 1

Explanation:

2MgO +O2=2MgO

From the balanced equation one mole of oxygen produce 80g of MgO .

number of moles of oxygen required to produce one gram MgO =1/80

Number of moles of oxygen required to produce 240g MgO =1/80×240=3moles

Answer 2

Answer:

The number of moles of oxygen to produce 240g magnesium oxide is 3 mol.

Explanation:

$2Mg + O_{2}$ → $2 MgO$

1 mole of oxygen reacts with 2 moles of magnesium to produce 2 moles of magnesium oxide.

To find the moles required to produce 240g of magnesium oxide, we have to convert the mass of magnesium oxide to moles.

The formula of mole is-

$Moles=\frac{Mass}{Molar Mass}$

The molar mass of magnesium oxide is- 40g/mol

$Moles=\frac{240}{40}=6mol$

When,

1 mole of oxygen → 2 moles of magnesium oxide

x mole of oxygen → 6 moles of magnesium oxide

$2 * x = 1 * 6$

$2x = 6$

$x = \frac{6}{2}$

$x = 3mol$