Question

calculate the power of an engine required to lift 100000 kg of coal from mine 360m deep.take g=10m/s

Answer 1

Hey there!

Mistakes in the question!
Question will be ---->
Calculate the power of an engine required to lift 100000 kg of coal per hour from a mine 360m deep.

Answer----->

Mass(m) = 100000 kg = 10^5 kg
Height (h) = 360m
Acceleration due to gravity = 10 m/s^2
Time(t) = 1 hour = 3600 s
Then,
P.E = mgh
      = 10^5 * 10 * 360 J
Work done = P.E = 10^5 * 10 * 360 J

We know,
Power = Work done / Time
            = 10^5 x 10 x 360/3600
            = 10^5 watt.

Hope It Helps You!

Answer 2

hope it helps you. .......