Question

calculate the total number of atoms present in 1.4g of dinitrogen.​

Answer 1

Answer:

YOU DON'T KNOW I WILL HELP YOU

Answer 2

Answer:

$6.022 \times {10^{23}}$ is known as Avogadro's number. Thus, the molecules of dinitrogen gas in $0.05{\text{ mol}}$ are $3.01 \times {10^{23}}{\text{ molecules}}$. Thus, the total number of electrons present in $1.4{\text{ g}}$ of dinitrogen gas are $4.214 \times {10^{23}}{\text{ electrons}}$.