Question

calculate the total resistance ​

Answer 1

Total resistance, $\sf{R_{eq}}$ = $\sf{\dfrac{19}{12}}$ Ω

Explanation:

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Given:

3 resistors, 2 connected parallel and 1 connected in series

$\sf{R_1}$ = 2Ω

$\sf{R_2}$ = 3Ω

$\sf{R_2}$ = 4Ω

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To Find:

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Total resistance, $\sf{R_eq}$

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Solution:

We know that

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$\sf{R_1}$ is connected in series

$\sf{R_2}$ and $\sf{R_3}$ are connected in parallel

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Now,

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$\sf{R_{eq}}$ = $\sf{R_s}$ + $\sf{\dfrac{1}{R_p}}$

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$\sf{R_s}$ = 2Ω

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$\sf{\dfrac{1}{R_p}}$ = $\sf{\dfrac{1}{3}}$ + $\sf{\dfrac{1}{4}}$ Ω

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$\sf{\dfrac{1}{R_p}}$ = $\sf{\dfrac{7}{12}}$ Ω

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$\sf{R_{eq}}$ = 2Ω + $\sf{\dfrac{7}{12}}$ Ω

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$\sf{R_{eq}}$ = $\sf{\dfrac{19}{12}}$ Ω