Question

Can explain me this question ​

Answer 1

$\huge\mathfrak\red{Answer}$

$y = (x + \frac{6}{x + 5} )( \frac{3x + 2}{ {x}^{2} + 5x + 6 } ) \\ \\ take \: lcm \\ \\ y = ( \frac{ {x}^{2} + 5x + 6 }{x + 5} )( \frac{3x + 2}{ {x}^{2} + 5x + 6 } ) \\ y = \frac{3x + 2}{x + 5} \\ \\ \frac{dy}{dx} = \frac{d( \frac{3x + 2}{x + 5} )}{dx} \\ \\ \frac{dy}{dx} = \frac{(x + 5) \frac{d(3x + 2)}{dx} - (3x + 2) \frac{d(x + 5)}{dx} }{ {(x + 5)}^{2} } \\ \\ \frac{dy}{dx} = \frac{(x + 5)(3) - (3x + 2)(1)}{ {(x + 5)}^{2} } \\ \\ \frac{dy}{dx} = \frac{3x + 15 - 3x - 2}{ {(x + 5)}^{2} } \\ \\ \frac{dy}{dx} = \frac{13}{ {( x + 5)}^{2} }$

Answer 2

Answer:

the before answer will help u

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