chapter name is identities and factorisation who can solve this
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maybe u can start it that way
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Step-by-step explanation:
Using identity (a+b)²=a²+2ab+b²
(√3a+√2b)²=(√3a)²+ 2×√3a×√2b+
(√2b)²
3a²+2√6ab+2b²
Pls mark it brainliest
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