Math, asked by iushe, 11 months ago

chapter name is identities and factorisation who can solve this

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Answered by yaya78

2

Answer:

maybe u can start it that way

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Answered by harshamish123

1

Answer:

Step-by-step explanation:

Using identity (a+b)²=a²+2ab+b²

(√3a+√2b)²=(√3a)²+ 2×√3a×√2b+

(√2b)²

3a²+2√6ab+2b²

Pls mark it brainliest

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