Question

Can you please give me the solution of this question of error analysis

Answer 1

Answer: (2) 60%

Solution:

percentage error in velocity = 30%

or, (%∆v) = 30%

since,

$KE = \frac{1}{2} m {v}^{2}$

hence,

%age error in KE = (%∆m) + 2(%∆v)

(%∆KE) = (%∆m) + 2(%∆v)

since, here any information about error in measurement of mass is not given,

we can take,

(%∆m) = 0..

so,

(%∆KE) = 2(%∆v) = 2×30% = 60%.....