ch 5 arithmetic progression
please answer it. It is very emergency.
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Step-by-step explanation:
given that
common difference in a= common difference in b
da=db
a100-b100=100
a+99d-(b+99d)=100
a+99d-b-99d=100
a-b=100 (1)
a=100+b
putting the value of a in common formula
100+b+99d-(b+99d)=100
100+b+99d-b-99d=100
100=100 will come
this means that if the d is same then the answer must be 100.
hope u like the answer :))))
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