Question

each being 10 cm. Find the area of the trapeziuni.
the figure AB and DC are parallel sides of a trapezium ABCD and LADC = 90.Given
AB = 15cm, CD = 40 cm and diagonal AC = 41 cm, calculate the area of the
ABCD​

Answer 1

Answer:

area of trapezium is 247.5

Step-by-step explanation:

lets first find AD by Pythagoras theorem

${ac}^{2} = {cd}^{2} + {ad}^{2}$

${41}^{2} = {40}^{2} + {ad}^{2}$

$1681 = 1600 + {ad}^{2}$

${ad}^{2} = 1681 - 1600 \\ {ad}^{2} = 81 \\ ad = \sqrt{81} \\ ad = 9$

now find area by formula of area of trapezium

$area = \frac{1}{2} \times hight \times (sum \: of \: base)$

$= \frac{1}{2} \times 9 \times (40 + 15) \\ = \frac{1}{2} \times 9 \times 55 \\ = \frac{1}{2} \times 495 \\ = 247.5$

HOPE IT HELPS AND IF IT HELPS THEN PLEASE MARK AS BRAINLIEST

HAVE A NICE DAY