circumference of the base of a 12m high wooden solid cone is 44m . find the volume of the cone and the TSA
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circumference of base of cone =44m
2 x 227/ x r =44m
r =7m
now
volume of cone=pi.r^2.h /3
=22/7 x 7 x 7 x 12/3m^3
=616 m^3
slant height=root {(7)^2+(12)^2}=13m
area of TSA=pi.r.l+pi.r^2
=22/7 x 7 x 13+ 22/7 x (7)^2
=440m^2
2 x 227/ x r =44m
r =7m
now
volume of cone=pi.r^2.h /3
=22/7 x 7 x 7 x 12/3m^3
=616 m^3
slant height=root {(7)^2+(12)^2}=13m
area of TSA=pi.r.l+pi.r^2
=22/7 x 7 x 13+ 22/7 x (7)^2
=440m^2
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