Question

class 9 math​question​

Answer 1

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In ∆ABC,

angle ABC= 69°

angle ACB= 31°

angle ABC+ angle ACB+angle BAC------angle sum property

69°+31°+angleBAC= 180°

100°+angleBAC= 180°

angle BAC = 180°-100°

angleBAC= 80°

angleBAC= angleBDC (angles in the same segments of circle are equal)

angle BAC= 80°

Therefore, angle BDC= 80°

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Answer 2

angle ABC = 69 degree

angle ACB = 31 degree

angle BDC =?

angle sum property =180

angleABC + angleBCA + angleCAB =180

69+31+angleCAB=180

angleCAB=180-100

angleCAB=80

so if angle CAB is of 80 then angleBDC is also of 80 because angle on the segment of circle makes equal angle