Math, asked by mdumarMd4642, 11 months ago

Compute the median for each of the following data
(i)Marks No.of students (ii)Marks No.of students
Less than 10 0 More than 150 0
Less than 30 10 More than 140 12
Less than 50 25 More than 130 27
Less than 70 43 More than 120 60
Less than 90 65 More than 110 105
Less than 110 87 More than 100 124
Less than 130 96 More than 90 141
Less than 150 100 More than 80 150

Answers

Answered by prathamlunkar3
1

Step-by-step explanation:

STATISTICS

Compute the median for each of the following data:

(i)Marks No. of students (ii)Marks No. of students

Less than 10 0 More than 150 0

Less than 30 10 More than 140 12

Less than 50 25 More than 130 27

Less than 70 43 More than 120 60

Less than 90 65 More than 110 105

Less than 110 87 More than 100 124

Less than 130 96 More than 90 141

Less than 150 100 More than 80 150

November 22, 2019avatar

Roopal Jinka

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ANSWER

(i)

Class interval Frequency Cumulative frequency

0−10 0 0

10−30 10 10

30−50 15 25

50−70 18 43

70−90 22 65

90−110 22 87

110−130 9 96

130−150 4 100

N=100

We have, N=100,

2

N

=50

The cumulative frequency just greater than

2

N

is 65 then median class is 70−90 such that,

l=70,h=90−70=20,f=22,cf=43

Median=l+

f

2

N

−cf

×h

⇒ Median=70+

22

50−43

×20

⇒ Median=70+

22

7×20

⇒ Median=70+6.36

∴ Median=76.36

(ii)

Class interval Frequency Cumulative Frequency

80−90 9 9

90−100 17 26

100−110 19 45

110−120 45 90

120−130 33 123

130−140 15 138

140−150 12 150

150−160 0 150

N=150

We have, N=150, then,

2

N

=

2

150

=75

The cumulative frequency just more than

2

N

is 90 then the median class is 110−120 such that

l=70,h=120−110=10,f=45,cf=45

Median=l+

f

2

N

−cf

×h

⇒ Median=110+

45

75−45

×10

⇒ Median=110+

45

30×10

⇒ Median=110+6.67

∴ Median=116.67

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