Question

Comstruct a quad EFGH where EF = 7.7 cm , FG = 6.8 cm , GH = 5.2 cm , EH = 4 cm and angle G = 120 degree​

Answer 1

Step-by-step explanation:

Given: In the Cyclic Quadrilateral EFGH

EF=5.2cm, ∠GEF=50

o

, FG=6cm and ∠EGH=40

o

.

Construction:

(i) Draw a rough diagram and mark the measurements. Draw a line segment EF=5.2cm.

(ii) From E, draw EX such that ∠FEX=50

o

.

(iii) With F as centre and radius 6cm, draw an arc intersecting EX at G.

(iv) Join FG.

(v) Draw the perpendicular bisectors of EF and FG intersecting each other at O.

(vi) With O as centre and OE(=OF=OG) as radius, draw a circumcircle.

(vii) From G, draw GY such that ∠EGY=40

o

which interscets the circle at H.

(viii) Join EH.

Now, EFGH is the required cyclic quadrilateral.