Question

considering the sum difference and product what are the missing numbers in the following​

Answer 1

Answer:

The two numbers are 6 and 7 and their difference is 7 - 6 = 1

Step-by-step explanation:

Let the two numbers be 'x' and 'y'.

According to the question,

x + y = 13  ⇒ x = 13 - y  ...   (i)

x * y = 42   ...   (ii)

Using x = 13 - y in equation (ii)

(13 - y) y = 42

13y - y² - 42 = 0

Multiplying the equation by -1, we get,

y² - 13y + 42 = 0   ...   (iii)

6 and 7 are factors of 42 and -13y can be written as (- 6y - 7y)

Re-writing equation (iii),

y² - 6y - 7y + 42 = 0

y (y - 6) - 7 (y - 6) = 0

(y - 6) (y -7) = 0

y - 6 = 0 or y - 7 = 0

y = 6 or 7

Using these values in equation (i)

x = 13 - 6 or 13 - 7

x = 7 or 6.

So, the two numbers are 6 and 7

And, their difference is 7 - 6 = 1