Question

Construct a triangle ABC in which AB =7cm, BC+CA= 9cm ,angle A=45°

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

According the question, we have to construct a triangle ABC in which AB =7cm, BC+CA= 9cm ,angle A=45°.

Let,s start to construct :-

• First we will draw AB = 7cm
• In this step we will construct ∠BAP = 45° from point A.
• Here we will cut  segment AD from the ray AP, AD = BC + CA= 9cm.
• Now we will join here B and D.
• In next step we have to construct perpendicular bisector of BD, which is meeting AD at point C.
• Here we will join B & C , and will get Δ ABC.

Hence, Δ ABC is the required Δ.

Ans :-Δ ABC is the required Δ.

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