if 9 times the 9th term of an AP, is equal to 13 times of 13th term then the 22nd term is
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Answered by
6
9(a+8d)=13(a+12d)
9a+72d=13a+156d
4a+84d=0
4(a+21d)=o
a+21d=0
9a+72d=13a+156d
4a+84d=0
4(a+21d)=o
a+21d=0
Answered by
16
Hi,
Here is your answer,
We know that, a = first term and d = common difference
According to the question,9 × t₉ = 13 t × 13
→ 9 (a+8d) = 13 (a+12d)
→ 9a + 72d = 13a + 156d
→ -4a = 84d
→ -a = 21d
→ a + 21d = 0 ∵ REQUIRED SOLUTION
↔ Therefore the 22nd term is 0.
Hope it helps you !
Here is your answer,
We know that, a = first term and d = common difference
According to the question,9 × t₉ = 13 t × 13
→ 9 (a+8d) = 13 (a+12d)
→ 9a + 72d = 13a + 156d
→ -4a = 84d
→ -a = 21d
→ a + 21d = 0 ∵ REQUIRED SOLUTION
↔ Therefore the 22nd term is 0.
Hope it helps you !
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