Question

Construct a triangle xyz in which y=30 z=90 and xy+yz+zx=11cm

Answer 1

Step-by-step explanation:

1. draw a line of 11 cm and name it AB
2. draw 30 on A and 90 on B
3. draw bisector of 30 and 90 that is 15 and 45
4. expand both lines till they donot meet
5. where they will meet it will our point X
6. now draw perpendicular bisector of 15 and 45
7. draw these line
8. where they will cut line AB, they will be respective points Y and Z..
9. Add measure of xy, yz and xz it will be your 11 cm.

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