Math, asked by nenicewAswardhita, 1 year ago

cosA/1-tanA - sin2A/cosA - sinA = sinA+cosA.

Answers

Answered by ARoy
3
cosA/1-tanA-sin²A/cosA-sinA
=cosA/(1-sinA/cosA)-sin²A/(cosA-sinA)
=cos²A/(cosA-sinA)-sin²A/(cosA-sinA)
=(cos²A-sin²A)/(cosA-sinA)
=(cosA+sinA)(cosA-sinA)/(cosA-sinA)
=sinA+cosA (Proved)
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