Question

Cosec^2 90 - theta -tangent ^2 = cos^2 90-theta + Cos ^ 2theta

Answer 1

Answer:

Step-by-step explanation:

Take the L. H. S

cosec^2(90°-theta)-tan^2

Using,cosec^2(90°-theta)=sec^2theta

=sec^2theta - tan^2theta

Using, sec^2theta = 1/cos^2theta

=1/cos^2theta - sin^2theta/cos^2theta

=(1 - sin^2theta)/cos^2theta

Using the identity,1 - sin^2theta=cos^2theta

= cos^2theta /cos^2theta

=1 .....(1)

Taking R. H. S.

=cos ^2 (90-theta) +cos ^2 theta

Using ,cos ^2 (90-theta) = sin^2theta

=sin^2theta + cos^2theta

Using the identity, sin^2theta + cos^2theta=1

=1 ......(2)

From (1) &(2)

L. H. S. = R. H.S.

Answer 2

Answer:

aNs in the pic

Step-by-step explanation:

refer to the pic.