Cylindrical cans of cricket ball are to be Packed in a box. The radius and height of each can is 8cm and 32 cm respectively. The length , breadth, height of the box are 68cm×52cm×50cm. What is the maximum number of cans that can be fit ?
Answers
If cylindrical cans of radius 8cm and height 32 cm is to be packed in a box of 68cm×52cm×50cm then the maximum number of cans that can be fit is 27.
Step-by-step explanation:
For Cylindrical Can:
Radius, r = 8 cm
Height, h = 32 cm
Therefore,
The volume a cylindrical can = πr²h = π * (8²) * 32 ….. (i)
For the box:
Length, l = 68 cm
Breadth, b = 52 cm
Height, h = 50 cm
Therefore,
The volume a box = length*breadth*height = 68 * 52 * 50 ….. (ii)
Thus,
The maximum no. of cans that can be fit into the box is,
= [Volume a box] / [Volume a cylindrical can]
= [68 * 52 * 50] / [π*(8²)*32] …. [substituting from (i) & (ii)]
= [68 * 52 * 50] / [(22/7) * 8 * 8 * 32]
= [176800] / [6436.57]
= 27.46
≈ 27
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Answer:
Step-by-step explanation:
Answer is 18
