Question

(D) 60
21. The H.C.F. and L.C.M. of two numbers is 18 and
252 respectively. If one number is 6 times of 21, the
six times of the other is 216, find the sum of both
these numbers​

Answer 1

Answer: Sum of the numbers = 162

Step-by-step explanation:

Let the numbers be x and y respectively.

HCF = 18, LCM = 252

Formula: HCF * LCM = Product of numbers = x*y

• x, y = 4536

Now,

x = 6 * 21

• x  = 126

6y = 216, y = 216/6

• y = 36

Note: The product of 126 and 36 is 4536. The HCF is 18 and LCM is 252.

Sum of the numbers = x + y

Sum = 126+36

∴ Sum of the numbers = 162

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