(D) 60
21. The H.C.F. and L.C.M. of two numbers is 18 and
252 respectively. If one number is 6 times of 21, the
six times of the other is 216, find the sum of both
these numbers
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Answer: Sum of the numbers = 162
Step-by-step explanation:
Let the numbers be x and y respectively.
HCF = 18, LCM = 252
Formula: HCF * LCM = Product of numbers = x*y
- x, y = 4536
Now,
x = 6 * 21
- x = 126
6y = 216, y = 216/6
- y = 36
Note: The product of 126 and 36 is 4536. The HCF is 18 and LCM is 252.
Sum of the numbers = x + y
Sum = 126+36
∴ Sum of the numbers = 162
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