D , E and F are the points on sides BC , CA and AB respectively of △ABC . Such that AD bisects ∠A , BE bisects ∠B and CF bisects ∠C . If AB = 5cm , BC = 8cm and CA = 4cm , determine AF , CE and BD ...Draw the fig also
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garv1510:
Thanks its perfect
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Figure:-
Given:-
- D , E and F are the points on sides BC , CA and AB respectively of △ABC .
- AB = 5cm , BC = 8cm and CA = 4cm
To find:-
- Find the value AF , CE and BD ...?
Solutions:-
- AB = 5cm, BC = 8cm and CA = 4cm
Since AD bisector of <A
So AB/AC = BD/CD
Then,
=> 5/4 = BD/ BC - BD
=> 5/4 = BD/8 - BD
=> 40 - 5BD = 4BD
=> 9BD = 40
So, BD = 40/9 cm.
Since BE is the bisector of <B.
=> AB/BC = AE/EC
=> AB/BC = AC - EC/EC
=> 5/8 = 4 - CE/CE
=> 5CE = 32 - 8CE
=> 5CE + 8CE = 32
=> 13CE = 32
So, CE = 32/13 cm.
Now since CF is the bisector of <C
So BC/CA = BF/AF
=> 8/4 = AB - AF/AF
=> 8/4 = 5 - AF /AF
=> 8AF = 20 - 4AF
=> 12AF = 20
So 3AF = 5
=> AF = 5/3 cm
Hence, the BD = 40/9, CE = 32/13 cm and AF = 5/3 cm.
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