Question

(d) Translate the following statements into chemical equations and then balance the equations:
(i) Ferric sulphate reacts with potassium
hydroxide to form potassium sulphate and ferric hydroxide.​

Answer 1

Answer:

$\sf Fe_2(SO_4)_3 + 6KOH \rightarrow 3K_2SO_4 + 2Fe(OH)_3$

Explanation:

Formula for Ferric Sulphate

→ $\sf Fe_2(SO_4)_3$

Potassium hydroxide

→ KOH

Potassium Sulphate

→ $\sf K_2SO_4$

Ferric Hydroxide

→ $\sf Fe(OH)_3$

So, the skeletal equation for this reaction would be

$\sf Fe_2(SO_4)_3 + KOH \rightarrow K_2SO_4 + Fe(OH)_3$

Now, On LHS, Fe = 2 and on RHS, Fe = 1

So, balance Fe.

$\sf Fe_2(SO_4)_3 + KOH \rightarrow K_2SO_4 + 2Fe(OH)_3$

Now, on LHS, K = 1 and on RHS, K = 2.

So, balance K

$\sf Fe_2(SO_4)_3 + 2KOH \rightarrow K_2SO_4 + 2Fe(OH)_3$

Now on LHS, S = 3 and on RHS, S = 1

So, balance S

$\sf Fe_2(SO_4)_3 + 2KOH \rightarrow 3K_2SO_4 + 2Fe(OH)_3$

Now, K got unbalanced so balance K again

$\sf Fe_2(SO_4)_3 + 6KOH \rightarrow 3K_2SO_4 + 2Fe(OH)_3$

Now, On LHS

Fe = 2

K = 6

O = 18

H = 6

On RHS,

Fe = 2

K = 6

O = 18

H = 6

Hence, the equation is balanced.

Answer 2

Answer:

This equation is already balanced...