Question

Date
Find the value of x for which (8x+4),(6x-2)and (2x+7) are in AP.
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Answer 1

Answer: 5.5

Step-by-step explanation:

If a, b, c are in a.p then 2b = a + c

So,

2(6x-2) = 8x+4+2x+7

12x-4 = 10x + 7

2x = 11

x=11/2

x = 5.5

Answer 2

Answer:

x = 15/2

Step-by-step explanation:

(8x+4), (6x-2), (2x+7) .........

a2 - a1 = a3 - a2

(6x - 2) - (8x + 4) = (2x + 7) - (6x - 2)

6x - 2 - 8x - 4 = 2x + 7 - 6x + 2

- 2x - 6 = -4x + 9

-2x + 4x = 9 + 6

2x = 15

x = 15/2

a1 = 8x + 4 = 8 × 15/2 + 4 = 60 + 4 = 64

a2 = 6x - 2 = 6×15/2 - 2 = 45 - 2 = 43

a3 = 2x + 7 = 2×15/2 + 7 = 15 + 7 = 22

the AP is

64, 43, 22, 1, ........

hope this helps you ,