Date
Find the value of x for which (8x+4),(6x-2)and (2x+7) are in AP.
Answers
Answered by
0
Answer: 5.5
Step-by-step explanation:
If a, b, c are in a.p then 2b = a + c
So,
2(6x-2) = 8x+4+2x+7
12x-4 = 10x + 7
2x = 11
x=11/2
x = 5.5
Answered by
0
Answer:
x = 15/2
Step-by-step explanation:
(8x+4), (6x-2), (2x+7) .........
a2 - a1 = a3 - a2
(6x - 2) - (8x + 4) = (2x + 7) - (6x - 2)
6x - 2 - 8x - 4 = 2x + 7 - 6x + 2
- 2x - 6 = -4x + 9
-2x + 4x = 9 + 6
2x = 15
x = 15/2
a1 = 8x + 4 = 8 × 15/2 + 4 = 60 + 4 = 64
a2 = 6x - 2 = 6×15/2 - 2 = 45 - 2 = 43
a3 = 2x + 7 = 2×15/2 + 7 = 15 + 7 = 22
the AP is
64, 43, 22, 1, ........
hope this helps you ,
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