Question

find three consecutive numbers such that seven times the smallest number may be equal to three times the sum of other two​

Answer 1

Answer:

9,10,11.

Step-by-step explanation:

Since the number are consecutive so

Let first number be x

let second number be x+1

let third number be x+2

according to question

7*x = 3(x+1+x+2)

7x = 3(2x+3)

7x = 6x+9

7x-6x = 9

x = 9

now first number = 9

second number = x+2 = 9+1 = 10

third number = x+2 = 9+2 = 11