Derive an expression for kinetic energy. A car before stopping moving at speed of 5m/s with passanger of mass 1200 kg and mass of car is 1180 kg. What is the work done by break to stop car?
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Answer:
car of mass m=1200kg moving initially at u=90m/s
=90×
18
5
=25m/s
let the braking force be given as,
f=−3600t [as f various linearly with time]
The braking force causes retardation,which given by :-
a=
m
f
=
1200
−3600t
=−3t
as, a=
dt
dv
=−3t ⇒∫
u
v
dv=∫
0
t
−3dt
=v−u=
2
3t
2
As u=25m/s , we get:-
v=
2
−3t
2
+25
when car comes to halt v=0 so:-
25=
2
3t
2
⇒t=
3
50
s
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