Determine the diode current at 20 c for a silicon diode with is=50na with an applied forward voltage 0.6v'
Answers
20 c for a silicon diode with is=50na with an applied forward voltage 0.6v'
Concept:
Shockley equation will be used to solve this question.
Given:
Current = 50 × 10⁻⁹ A
Temperature = 20°C or 293 K
Voltage = 0.6 Volt
Silicon Diode so n = 2
Find:
Diode current
Solution:
Shockley equation is for P-N junction or diode.
Id = Is ( ( e ^ (qVd/nKT) ) - 1 )
Where Is is the reverse saturation current
q is charge on electron
Vd is applied voltage
n is ideality factor
K is Boltzmann's constant
T is temperature in kelvin
for silicon diode ideality factor (n) = 2
charge on electron = 1.6 × 10⁻¹⁹ coulombs
Boltzmann's constant = 1.38 × 10⁻²³ m² kg s⁻² K⁻¹
Putting everything in equation
Id = Is ( ( e ^ (qVd/nKT) ) - 1 )
Id = 50 × 10⁻⁹ ( ( e ^ ((1.6 × 10⁻¹⁹)×0.6/2×(1.38 × 10⁻²³)×293) ) - 1 )
Id = 50 × 10⁻⁹ ( ( e ^ ((0.96 × 10⁻¹⁹)/(808.68 × 10⁻²³) ) - 1 )
Id = 50 × 10⁻⁹ ( ( e ^ 11.87 ) - 1 )
Id = 50 × 10⁻⁹ ( ( 142914.2387) - 1 )
Id = 50 × 10⁻⁹ × ( 142913.2387 )
Id = 7145662 × 10⁻⁹
Id = 7.145662 × 10⁻³ Ampere
Id = 7.15 × 10⁻³ Ampere (approximately) or 7.15 mA (approximately)
Hence, The diode current will be 7.15 mA (approximately).
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