Question

determine the nature of the root of the equation 2x^2+5root3x6=0​

Answer 1

The Roots of the equation (2x² + 5√3x + 6 = 0) are Real and Distinct

Explanation:

2x² + 5√3x + 6 = 0

D = b² - 4ac

D = (5√3)² - 4(2)(6)

D = (25x3) - 48

D = 75 - 48

D = 27

Therefore, D > 0

Therefore, The Roots of the equation (2x² + 5√3x + 6 = 0) are Real and Distinct

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