diagonals of a rhombus are in the ratio 3:4 perimeter is 40 cm find the length of the diagonals
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hiii!!!
here's ur answer...
given the perimeter of the rhombus is 40cm.
therefore side × 4 = 40cm
==> side = 40/4
==> side = 10cm
now,
given that the diagonals are in ratio 3:4.
let the diagonals be 3x and 4x.
we know that the diagonals of a rhombus bisect each other in the centre.
let hypontuse be the side of the rhombus.
by Pythagoras thereom:-
a² + b² = c²
==>(3x/2)² + (4x/2)² = 10²
==> 9x²/4 + 16x²/4 = 100
==> 9x²+16x²/4 = 100
==> 25x²/4 = 100
==> x²/4 = 100/25
==> x²/4 = 4
==> x² = 4 × 4
==> x² = 16
==> x = √16
==> x = 4cm
hence, diagonals of the rhombus are:-
→ 3x = 3 × 4
= 12cm
→ 4x = 4 × 4
= 16cm
hope this helps u..!!
here's ur answer...
given the perimeter of the rhombus is 40cm.
therefore side × 4 = 40cm
==> side = 40/4
==> side = 10cm
now,
given that the diagonals are in ratio 3:4.
let the diagonals be 3x and 4x.
we know that the diagonals of a rhombus bisect each other in the centre.
let hypontuse be the side of the rhombus.
by Pythagoras thereom:-
a² + b² = c²
==>(3x/2)² + (4x/2)² = 10²
==> 9x²/4 + 16x²/4 = 100
==> 9x²+16x²/4 = 100
==> 25x²/4 = 100
==> x²/4 = 100/25
==> x²/4 = 4
==> x² = 4 × 4
==> x² = 16
==> x = √16
==> x = 4cm
hence, diagonals of the rhombus are:-
→ 3x = 3 × 4
= 12cm
→ 4x = 4 × 4
= 16cm
hope this helps u..!!
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