Question

Divide 19 into two parts such that sum of their square is 193

Answer 1

Let the first part be x 
the second part will be 19-x
x² + (19-x)² = 193 
x² + 361 + x² - 38x = 193 
2x² - 38x + 168 = 0 
factorising it, we get 
2x² - 14x - 24x +168 = 0
2x(x- 7) - 24 (x - 7) = 0
(2x - 24) (x - 7) = 0
x = 12 and x = 7 are the two parts 

Answer 2

Answer:

x = 12 and x = 7 are the two parts 

Step-by-step explanation:

Let the first part be x 

the second part will be 19-x

x² + (19-x)² = 193 

x² + 361 + x² - 38x = 193 

2x² - 38x + 168 = 0 

factorising it, we get 

2x² - 14x - 24x +168 = 0

2x(x- 7) - 24 (x - 7) = 0

(2x - 24) (x - 7) = 0

x = 12 and x = 7 are the two parts