Question

Divide 20 into parts such that the difference between there square is 160

Answer 1

Hi, maths aryabhatta here


Let the parts be x and y

Then,

x²-y²=160

(x+y) (x-y) =160

20(x-y) =160

(x-y) =160/20

x-y=8. ---------1equation

x+y=20 --------2equation

Add both the equations

x+y=20
x-y=8

2x=28
x=28/2

x=14

Put the value of x in 1equation

x-y=8

14-8=y

6=y

Verification,

14²-6²=160

196-36=160

160=160

Hence the numbers are 14 and 6