divide
x +{2x}^{2} + {3x}^{4} - {x}^{5} \: by \:2 xdividex+2x
2
+3x
4
−x
5
by2x
Answers
Answered by
2
Step-by-step explanation:
By remainder theorem,
f(x)=q(x)g(x)+r(x)
∴2x
5
+3x
4
+4x
3
+4x
2
+3x+2=(2x
2
+x+1)(x
3
+x
2
+x+1)+r(x)
=2x
2
(x
3
+x
2
+x+1)+x(x
3
+x
2
+x+1)+1(x
3
+x
2
+x+1)+r(x)
=2x
5
+2x
4
+2x
3
+2x
2
+x
4
+x
3
+x
2
+x+x
3
+x
2
+x+1+r(x)
=2x
5
+3x
4
+4x
3
+4x
2
+2x+1+r(x)
r(x)=x+1
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