Question

Draw a circle of radius 5cm.draw any two chords and make their perpendicular bisectors as well.where do these bisectors meet?

Answer 1

Answer:

its very simple

Step-by-step explanation:

• first of all we will make a circle of 5 cm
• and then draw its chord means diameter
• and bisect the first
• and the bisect the second

I will showing you

hope this is helpful for you

thank you so much

Answer 2

Answer:

The bisectors meet at point  O ,which is the centre of the cirlce

Step-by-step explanation:

Explanation :

First we draw a circle of radius 5 cm with centre O.

Then draw any two chords in the circle ,

so let AB and CD be the two chord .

Now , from point A as a centre take radius more than half of AB

 and draw two arcs one on each side of AB .

Again , from point B as a centre take radius more than half of AB

and draw two arcs one on each side of AB  which cut the

previous arcs .

then , plot  point P,Q,R and S at which the arcs cut each other.

Now , join the point  PQ and also join the point RS

So, PQ is the perpendicular bisector of chord AB  

and RS is the perpendicular bisector of CD.

Here we can see that bisectors PQ and RS meet at centre O.

Final answer:

Hence ,  the figure is given below and the perpendicular bisectors meet at O , the centre of the circle.