Draw ∆ABC with AB = 5 cm, AC = 3.5 cm and ∠BAC = 90⁰. What type of triangle is this??
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Answer:
STEPS:
- Draw a line AC = 5cm.
- Draw an angle of 90° at a point A.
- Taking A as center, Draw an arc of 5cm.
- The intersection of an arc on A at 5cm be B.
- Join the line AC.
- ∠BAC = 90⁰
- Hence, ∆BAC is a required triangle.
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