Question

Draw the graph of the equation x+y=8 and check whether x=3 and y=4 is a solution ornot.​

Answer 1

Answer:

(i)Solution:

Given equations are 3x + y + 4 = 0

6x – 2y + 4 = 0

Here a1 = 3, b1 = 1, c1 = 4

a2 = 6, b2 = –2, c2 = 4

\frac{a_{1}}{a_{2}}= \frac{3}{6}= \frac{1}{2},\frac{b_{1}}{b_{2}}= \frac{-1}{2},\frac{c_{1}}{c_{2}}= \frac{4}{4}= \frac{1}{1}

\frac{a_{1}}{a_{2}}\neq \frac{b_{1}}{b_{2}}

Hence the given pair of linear equations are intersecting at one point.

Hence given pair of linear equations is consistent

Let as plot the graph of given equations

In equation 3x + y + 4 = 0

x 0 -1 -2

y -4 -1 2

In equation 6x – 2y + 4 = 0

x 0 -1 -2

y 2 -1 -4

Here two lines AB and CD intersect at only one point that is E.Hence given pair of linear equation is consistent.