Question

draw two radii in a circle of radius 3.5cm such that the angle between the radius is 120degree. Construct two tangents at the end of the radii

Answer 1

Given the angle QPR is 60' and since angle at the center is double the angle between tangents
It may help u.

Answer 2

Solution :-

Step first : Take a point O on the plane and draw a circle of radius OA = 3.5 cm

Step second : Draw a ∠AOB = ∠AOC = 30° at O.

Step third: Draw a BX ⊥ OB and CX ⊥ OC at B and C respectively. BX and CS intersects at X.

Here,

BX and CX are two tangents Angele to the circle inclined to each other at 120°.

justification:

∠XOB = 30°

∠OBX = 90°

In ΔBOX,

∠XOB + ∠OBX + ∠BXO = 180°

∴ 30° + 90° + ∠BXO = 180°

⇒ ∠BXO = 180° – 120° = 60°

Similarly, ∠CXO = 60°

∴ ∠BXC = ∠BXO + ∠CXO = 60° + 60° = 120°

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@GauravSaxena01