plss solve this question it is urgent
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Step-by-step explanation:
Here given information concludes that
∠CBA= ∠CDB
∠CAB = ∠CDA
∠CDB+ ∠CDA= ∠CBA+∠CAB .......... EQUATION (1)
∠CBA+ ∠CAB+ ∠ACB= 180 °
∠CBA+ ∠CAB=180-∠ACB ...........EQUATION (2)
Equation both equations (1) & (2)
∠CDB+ ∠CDA= 180-∠ACB
Here,
∠CDB+ ∠CDA= ∠ADB ..............EQUATION (3)
PUTTING THE VALUE IN ABOVE EQUATION
∠ADB= 180-∠ACB
∠ADB+ ∠ACB= 180°
HENCE PROVED
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