Question

each cell contain 1 bit of _____ .​

Answer 1

Answer:

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Answer 2

Answer:

There is almost no chance that your memory is bit-addressed. The most likely situation is that your addresses are byte-addresses. And when you get the value of a 32-bit variable, the question is whether that address points at the Most Significant Byte or the Least Significant Byte of that 4-byte value - which is architecture dependent (e.g. x86 is little-endian, while MIPS is big-endian).

To give you an example in C, assuming your variable var has the value 0xDEADBEEF it might be stored in memory in one of two ways:

Big-Endian (because the address 0x125 points to the MSB