Question

equal volume of solution with ph 4 and ph 10 are mixed. what will be the approximate ph of final solution​

Answer 1

Dear Student,

● Answer -

pH = 7

◆ Explanation -

H+ concentration of solutions is related to pH as -

[H+] = antilog(-pH)

For pH = 4,

[H+] = antilog(-4)

[H+] = 10^-4 M

For pH = 10,

[H+] = antilog(-10)

[H+] = 10^-10 M

When these 2 solutions are added, concentration of the mixture will be -

[H+] = √(10^-10 × 10^-4)

[H+] = √(10^-14)

[H+] = 10^-7 M

So now, pH of the mixture will be

pH = -log(10^-7)

pH = 7

Hence, the resulting mixture is neutral.

Thanks dear...