Math, asked by manyaaa7903, 1 year ago

evaluate root 2 plus root 3 the whole square plus root 5 minus root 2 the whole square

Answers

Answered by MaheswariS
62

Answer:

(\sqrt{2}+\sqrt{3})^2+(\sqrt{5}-\sqrt{2})^2=12+2\sqrt{6}-2\sqrt{10}

Step-by-step explanation:

The given expression is evaluated by using suitable algebraic identities.

Formula used:

(a+b)^2=a^2+b^2+2ab\\\\(a-b)^2=a^2+b^2-2ab

Now,

(\sqrt{2}+\sqrt{3})^2+(\sqrt{5}-\sqrt{2})^2\\\\=(\sqrt{2})^2+(\sqrt{3})^2+2\sqrt{2}\sqrt{3}+(\sqrt{5})^2+(\sqrt{2})^2-2\sqrt{5}\sqrt{2}\\\\=2+3+2\sqrt{6}+5+2-2\sqrt{10}\\\\=12+2\sqrt{6}-2\sqrt{10}

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