Math, asked by nghjj298, 1 year ago

Find the nature of the roots of equation x*2 -3x -10 = 0

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Answered by simran206
20
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x {}^{2} - 3x - 10 \\ \\ Comparing \: the \: given \: eq.with \: ax {}^{2} + bx + c \\ a = 1 \\ b = - 3 \\ c = - 10 \\ \\ As \: we \: know \: that : \\ \\ Discrimi nant \: (d) = b {}^{2} - 4ac \\ \\ = &gt; ( - 3) {}^{2} - 4(1)( - 10) \\ \\ = &gt; 9 + 40 \\ \\ = &gt; 49 &gt; 0 \\ So, \: b {}^{2} - 4ac &gt; 0 \\ \\ Hence, \:Two \: distinct \: real \: roots \: exist \: for \: the \: given \: equation<br /> \\ = &gt; x {}^{2} - 3x - 10 \\ = &gt; x {}^{2} - 5x + 2x - 10 \\ = &gt; x(x - 5) + 2(x - 5) \\ = &gt; (x + 2)(x - 5) \\ So, \: The \: real \: roots \: are \: - 2 \: and \: 5
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Answered by Anonymous
8
hey mate here is ur answer....
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