Math, asked by shettysaish05, 6 months ago

Exam. : Std. X: Maths - 1 (Algebra): 88
Product of digits in two digit numbe
18. If 63 is subtracted from that num
the digits are interchanged so t
number is
(1) 29 (2) 92 (3) 36 (4) 8

Answers

Answered by shawmallika0
1

Answer:

I don't know bro and I cannot help also you in the exam it is not valid and I should not do that

Answered by Ahensammu
0

Answer:

92

Step-by-step explanation:

Let, the digit at unit's place =x

∴ Let the digit at ten's place

x

18

∴ Required number =

x

180

+x

Number formed by interchanging the digits

=10x+

x

18

According to given condition, we have

x

180

+x−63=10x+

x

18

i.e., 180+x

2

−63x=10x

2

+18

9x

2

+63x−162=0

x

2

+7x−18=0

x

2

+9x−2x−18=0

x(x+9)−2(x+9)=0

(x+9)(x−2)=0

∴ Rejectin x=−9, we get x=2

∴ Required No. =

x

180

+x

=

2

180

+2=92.

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