Exam. : Std. X: Maths - 1 (Algebra): 88
Product of digits in two digit numbe
18. If 63 is subtracted from that num
the digits are interchanged so t
number is
(1) 29 (2) 92 (3) 36 (4) 8
Answers
Answered by
1
Answer:
I don't know bro and I cannot help also you in the exam it is not valid and I should not do that
Answered by
0
Answer:
92
Step-by-step explanation:
Let, the digit at unit's place =x
∴ Let the digit at ten's place
x
18
∴ Required number =
x
180
+x
Number formed by interchanging the digits
=10x+
x
18
According to given condition, we have
x
180
+x−63=10x+
x
18
i.e., 180+x
2
−63x=10x
2
+18
9x
2
+63x−162=0
x
2
+7x−18=0
x
2
+9x−2x−18=0
x(x+9)−2(x+9)=0
(x+9)(x−2)=0
∴ Rejectin x=−9, we get x=2
∴ Required No. =
x
180
+x
=
2
180
+2=92.
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