Express tan θ in terms of tan α, if sin(θ + α) = cos (θ + α)
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Answer:
Tanθ = (1 - tanα)/(1 + tanα)
Step-by-step explanation:
sin(θ + α) = cos (θ + α)
Using Sin( A + B) = SinACosB + CosASinB
& Cos(A + B) = CosACosB - SinASinB
=> SinθCosα + CosθSinα = Cosθcosα - SinθSinα
=> SinθCosα + SinθSinα = Cosθcosα - CosθSinα
=> Sinθ (Cosα + Sinα) = Cosθ(Cosα - Sinα)
=> SinθCosα(1 + tanα) = CosθCosα(1 - tanα)
Dividing both sides by CosθCosα
=> Tanθ(1 + tanα) = (1 - tanα)
=> Tanθ = (1 - tanα)/(1 + tanα)
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