Factorisation by regrouping
1. x(x+y-z)-yz
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Given algebraic expression is x (x + y - z) - y z
Let us ungroup the third term with z from parentheses.
x (x + y) - x z - y z
= x ( x + y) - ( x + y) z
= (x - z) × (x + y)
If we fully expand the given expression, we get 4 terms.
x^2 + x y - x z - y z
We can also regroup 2nd term and 4th term together. 1st and 3rd terms together.
= x^2 - x z + x y - y z
= x(x - z) + y (y - z) = (x - z) × (x + y)
Let us ungroup the third term with z from parentheses.
x (x + y) - x z - y z
= x ( x + y) - ( x + y) z
= (x - z) × (x + y)
If we fully expand the given expression, we get 4 terms.
x^2 + x y - x z - y z
We can also regroup 2nd term and 4th term together. 1st and 3rd terms together.
= x^2 - x z + x y - y z
= x(x - z) + y (y - z) = (x - z) × (x + y)
kvnmurty:
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Answered by
0
Answer:
Given algebraic expression is x (x + y - z) - y z
Let us ungroup the third term with z from parentheses.
x (x + y) - x z - y z
= x ( x + y) - ( x + y) z
= (x - z) × (x + y)
If we fully expand the given expression, we get 4 terms.
x^2 + x y - x z - y z
We can also regroup 2nd term and 4th term together. 1st and 3rd terms together.
= x^2 - x z + x y - y z
= x(x - z) + y (y - z) = (x - z) × (x + y)
Step-by-step explanation:
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