factorise 56x^2y^2-14x^2
write correct answer and show it's process
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Answered by
4
Answer:
56x²y²-14x²=14x²(2y+1)(2y-1)
Step-by-step explanation:
Given that:-
56x²y²-14x²
=>(4×14)x²y²-(14×1)x²
Taking 14x² as common
=>14x²(4y²-1)
=>14x²[(2y)²-1²]
=>14x²(2y+1)(2y-1)
(since (a+b)(a-b)=a²-b²))
56x²y²-14x²=14x²(2y+1)(2y-1)
Answered by
3
Answer:
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