Question

Factorise the given expressions

(i) p2 -q
a2+6a+8​

Answer 1

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Answer 2

Answer:

(I) p²-q then p=-√q,+√q

(II)a²+6a+8 then a=-2,-4

Step-by-step explanation:

(I) let f(p)=p²-q

p²-q = p²-(√q)²

= (p-√q)(p+√q)

;put f(p)=0

;(p-√q)(p+√q) = 0

;Then ,

p= -√q,+√q

(II) let f(x) = a²+6a+8

= a²+(4a+2a)+8

= a²+4a+2a+8

= a(a+4)+2(a+4)

=(a+4)(a+2)

;put f(x) = 0

; (a+4)(a+2)=0

;Then ,

a= -4,-2