Question

factorise

x²+3√3x+6.........​

Answer 1

Answer:

This is my explanation.

HOPE YOU LIKE IT

Answer 2

$\boxed{ {x}^{2} \sqrt[3]{3x} + 6}$

Factorise .

$\color{red} \huge \boxed{1st \: step}$

First step is .

Multiply x² i.e first term by 6 i.e last term

x²*6=6x²

$\color{blue} \huge \boxed{2nd \: step}$

Second step means split middle term i.e

3√3x

It should split in that way

so the sum or subtract of two numbers would be 6x² and multiple of same number would be 3√3x

Hence make factor of 3

by adding or subtracting two numbers.

1+2=3

4-1=3

Use any one from above ...

$\huge \boxed{3rd \: step}$

See ....if we use 1+2 or 2+1

then answer would be ...

2√3+1√3= 3√3 ...( by adding)

if we multiple same number...Is the ans will be 6x²??????

YES .....

SOLVE .⬇️

2√3x * 1√3x

2x*3x

=> 6x²

NOW COME ON QUESTION....

SOLUTION..

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${x}^{2} + \sqrt[3]{3x} + 6 \\ \\ {x}^{2} + \sqrt[2]{3x} + \sqrt[1]{3x} + 6 \\ \\ x(x + \sqrt[2]{3} ) \: + \sqrt{3} (x + \sqrt[2]{3} ) \\ \\ (x + \sqrt[2]{3} )(x + \sqrt{3} )$

(x+2√3)=0 x+√3=0

x=(-2√3) x=(-√3)

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Hope ________Its helps u ...❤️❤️☺️☺️

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