Question

There are 4 numbers ,the H.C.F of each pair is 7 and the L.C.M of all numbers is 1470, then the product of the 4 numbers ?

Answer 1

Answer:

HCF × LCM = product of given numbers

Step-by-step explanation:

7 × 1470 = 10290

Answer 2

Answer:

504210

Step-by-step explanation:

Since the HCF of each pair = 7, let the four numbers be 7a, 7b, 7c, 7d.

Also, the number are relative prime so,

LCM=abcd×HCF

⇒abcd= 1470/7=210

​Therefore, product of numbers=7a*7b*7c*7d

                                                   =(7∧4)*abcd

                                                   =(7^4)*210= 2401*210=504210